e1.emp_name=e2.emp_name and e1.salary=e2.salary);
EMP_ID EMP_NAME SALARY
---------- ---------------------------------------- ----------
1 sunshine 10000
3 xyz 30000
2 semon 20000
2. 删除的几种方法:
(1)通过建立临时表来实现
SQL>create table temp_emp as (select distinct * from employee)
SQL> truncate table employee; (清空employee表的数据)
SQL> insert into employee select * from temp_emp;
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